18(18+14)=8x^2

Solution for 18(18+14)=8x^2 equation:

18(18+14)=8x^2

We move all terms to the left:

18(18+14)-(8x^2)=0

We add all the numbers together, and all the variables

-8x^2+1832=0

a = -8; b = 0; c = +1832;
Δ = b2-4ac
Δ = 02-4·(-8)·1832
Δ = 58624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{58624}=\sqrt{256*229}=\sqrt{256}*\sqrt{229}=16\sqrt{229}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{229}}{2*-8}=\frac{0-16\sqrt{229}}{-16}
=-\frac{16\sqrt{229}}{-16}
=-\frac{\sqrt{229}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{229}}{2*-8}=\frac{0+16\sqrt{229}}{-16}
=\frac{16\sqrt{229}}{-16}
=\frac{\sqrt{229}}{-1}
$